Mathematical Puzzles: What is () + () + () = 30 using 1,3,5,7,9,11,13,15?
My question had been merged with another one and as a result, I have added the previous answer to the present one. Hopefully this provides a clearer explanation. Just using the numbers given there, it's not possible, because odd + odd = even, even + odd = odd. 30 is an even number, the answer of 3 odd numbers must be odd, it's a contradiction. If what people say is true, then the question is wrongly phrased its any number of operations within those three brackets must lead to 30. Then it becomes a lot easier. Such as 15 + 7 + (7 + 1). That would give 30. But it assumes something that the question does not state explicitly and cannot be done that way. I still stick to my first point, it can't be done within the realm of math and just using three numbers, if not, then the latter is a way to solve it.EDIT: This question has come up many times, Any odd number can be expressed as the following, Let [math]n, m, p[/math] be an odd number, [math] n = 1 (mod[/math] [math]2), m = 1 (mod[/math] [math]2), p = 1 (mod[/math] [math]2)[/math][math]n+m+p = 1 + 1 + 1 (mod[/math] [math]2)[/math]Let's call [math]n+m+p[/math] as [math]x[/math][math]= x = 3 (mod[/math] [math]2)[/math]Numbers in modulo n can be added, I'll write a small proof for it below, [math]a = b (mod[/math] [math]n), c = d (mod[/math] [math]n)[/math][math]a+c = b+d (mod[/math] [math]n)[/math]We can rewrite [math]b[/math] and [math]d[/math] in the following way, [math]n | (b - a) = b-a = n*p[/math] (for some integer p) [math]b = a + np[/math][math]b = a + np, d = c + nq[/math][math]b + d = a + np + c + nq[/math][math]b+d = a + c + n(p + q)[/math]Now we have shown that our result is true, moving forward, [math]3 = 1 (mod[/math] [math]2)[/math][math]x = 1 (mod[/math] [math]2)[/math]Therefore the sum of three odd numbers can never be even. It will always be congruent to 1 in mod 2.(This was what I wrote for a merged answer).Modular arithmetic - Link on modular arithmetic, the basic operations. Modular multiplicative inverse - The multiplicative inverse in modular operations.Congruence relationFermat's little theorem Modular exponentiation - As title suggests.Good luck!
How does one get invited to the Quora Partner Program? What criteria do they use, or is it completely random?
I live in Germany. I got an invite to the Quora partner program the day I landed in USA for a business trip. So from what I understand, irrespective of the number of views on your answers, there is some additional eligibility criteria for you to even get an email invite.If you read the terms of service, point 1 states:Eligibility. You must be located in the United States to participate in this Program. If you are a Quora employee, you are eligible to participate and earn up to a maximum of $200 USD a month. You also agree to be bound by the Platform Terms (https://www.quora.com/about/tos) as a condition of participation.Again, if you check the FAQ section:How can other people I know .participate?The program is invite-only at this time, but we intend to open it up to more people as time goes on.So my guess is that Quora is currently targeting people based out of USA, who are active on Quora, may or may not be answering questions frequently ( I have not answered questions frequently in the past year or so) and have a certain number of consistent answer views.Edit 1: Thanks to @Anita Scotch, I got to know that the Quora partner program is now available for other countries too. Copying Anuta’s comment here:If you reside in one of the Countries, The Quora Partner Program is active in, you are eligible to participate in the program.” ( I read more will be added, at some point, but here are the countries, currently eligible at this writing,) U.S., Japan, Germany, Spain, France, United Kingdom, Italy and Australia.11/14/2018Edit 2 : Here is the latest list of countries with 3 new additions eligible for the Quora Partner program:U.S., Japan, Germany, Spain, France, United Kingdom, Italy, Canada, Australia, Indonesia, India and Brazil.Thanks to Monoswita Rez for informing me about this update.
Can you add 5 odd numbers to get 30?
It is 7,9 + 9,1 + 1 + 3 + 9 = 30Wish you can find the 7,9 and 9,1 in the list of1,3,5, 7,9 ,11,13,151,3,5,7, 9,1 1,13,15
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How do I get the 30 as addition of any five odd numbers? If numbers are 1,3,5,7,9,11,13,15 you can repeat the numbers.
There is no mention if you can use sign or not and thus the only possible way to get this is as follows: (15 - 9) + (13 - 7) + (7 - 1) + (9 - 1) + (13 - 9). If you solve inside the brackets, you will get the following equation 6 + 6 + 6 + 8 + 4. Adding all these numbers will give you 30if the question would be-Q4: ( ) + ( ) + ( ) + ( ) + ( ) = 30This is what you have for the equation. The following are the numbers that you can use to fill in the brackets: 1, 3, 5, 7, 9, 11, 13 and 15. You can repeat the numbers if required. The resulting sum should be 30.
How many questions out of 130 do I need to answer correctly to make 80%?
Let n = the number of questions out of 130 that need to be answered correctly to make a score of 80%.n/130 = 80%n/130 = 80/100n/130 = .80130(n/130)= 130(.80)(130/130)n = 130(.80)(1)n = 104n = 104CHECK:n/130 = 80%104/130 = 80%.80 = 80%80/100 = 80%80% = 80%Therefore, n = 104 questions out of 130 is indeed the number that needs to be answered correctly to make a score of 80%.
